Solving for time with the quadratic square root being subtracted.

initial vertical velocity (v _{y0})= 0 = 0 meter/second |

acceleration of gravity (g) = 0 = 0 meter/second^2 |

vertical displacement at time (Δy) = 0 = 0 meter |

time (t) = NOT CALCULATED |

Select to solve for a different unknown

vertical velocity

vertical velocity at time | |

initial vertical velocity | |

acceleration of gravity | |

time |

vertical displacement

vertical displacement at time | |

initial vertical velocity | |

time - quadratic square root added | |

time - quadratic square root subtracted | |

acceleration of gravity |

horizontal velocity

horizontal velocity at time |

horizontal displacement

horizontal velocity at time | |

initial horizontal velocity | |

time |

Range given projection angle and

equal initial and final elevations

equal initial and final elevations

range | |

initial velocity | |

acceleration of gravity |

References - Books:

Tipler, Paul A.. 1995. Physics For Scientists and Engineers. Worth Publishers. 3rd ed.

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