Solving for time with the quadratic square root being subtracted.

initial vertical velocity (v_{y0})

= 0

= 0

meter/second

acceleration of gravity (g)

= 0

= 0

meter/second^2

vertical displacement at time (Δy)

= 0

= 0

meter

time (t)

= NOT CALCULATED

Select to solve for a different unknown

vertical velocity

vertical velocity at time | |

initial vertical velocity | |

acceleration of gravity | |

time |

vertical displacement

vertical displacement at time | |

initial vertical velocity | |

time - quadratic square root added | |

time - quadratic square root subtracted | |

acceleration of gravity |

horizontal velocity

horizontal velocity at time |

horizontal displacement

horizontal velocity at time | |

initial horizontal velocity | |

time |

Range given projection angle and

equal initial and final elevations

equal initial and final elevations

range | |

initial velocity | |

acceleration of gravity |

References - Books:

Tipler, Paul A.. 1995. Physics For Scientists and Engineers. Worth Publishers. 3rd ed.

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