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Inductive reactance equals 2 pi times frequency times inductance

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Inductive Reactance

Inductive reactance increases with frequency because an inductor opposes changes in current. At DC (0 Hz), an ideal inductor has zero reactance. The result is measured in ohms.

X_L = 2πfL

Capacitive Reactance

Capacitive reactance falls with frequency because a capacitor passes higher-frequency current more easily. Together, resistance and reactance combine into impedance: Z = √(R² + X²).

X_C = 1 / (2πfC)

How It Works

Reactance is the opposition to AC current caused by inductors and capacitors. Unlike resistance, reactance changes with frequency. Inductive reactance (Xₗ = 2πfL) rises with frequency, while capacitive reactance (Xᴄ = 1/2πfC) falls. This calculator solves either equation for any unknown variable. The results are measured in ohms, the same unit as resistance. Together, resistance and reactance combine into impedance: Z = √(R² + X²).

Example Problem

A 10 mH inductor operates in a 60 Hz power circuit. What is its inductive reactance?

  1. Convert inductance: L = 10 mH = 0.01 H
  2. Apply the formula: Xₗ = 2π × 60 × 0.01 = 3.77 Ω

For a 100 µF capacitor at the same 60 Hz: Xᴄ = 1/(2π × 60 × 0.0001) = 26.53 Ω.

When to Use Each Variable

  • Solve for Reactancewhen you know the frequency and the component value (inductance or capacitance), e.g., finding the opposition a 10 mH inductor presents at 60 Hz.
  • Solve for Frequencywhen you need the frequency that produces a specific reactance, e.g., tuning an LC filter to resonate at a target impedance.
  • Solve for Inductancewhen you know the reactance and frequency and need to select an inductor, e.g., choosing a choke for a power supply filter.
  • Solve for Capacitancewhen you know the reactance and frequency and need to select a capacitor, e.g., sizing a coupling capacitor for an audio crossover.

Key Concepts

Reactance is measured in ohms like resistance, but it shifts the phase between voltage and current rather than dissipating energy. Inductive reactance grows linearly with frequency, while capacitive reactance shrinks inversely. When both are present, they partially cancel: the net reactance is X = X_L − X_C, and at resonance (X_L = X_C) the circuit behaves as a pure resistance.

Applications

  • Power systems: sizing capacitor banks for power factor correction on industrial motors
  • Audio engineering: designing crossover networks that split signals between woofers and tweeters
  • RF design: tuning LC tank circuits to select a specific radio frequency
  • Signal filtering: calculating cutoff frequencies for low-pass and high-pass RC/RL filters

Common Mistakes

  • Forgetting to convert units — inductance must be in henries and capacitance in farads, not millihenries or microfarads, before plugging into the formula
  • Confusing reactance with impedance — reactance is the imaginary component only; impedance combines both resistance and reactance as Z = sqrt(R^2 + X^2)
  • Using DC resistance values for AC analysis — at non-zero frequency, inductors and capacitors contribute reactance that pure resistance calculations ignore

Frequently Asked Questions

What is the difference between reactance and impedance?

Reactance is the opposition to AC current from inductors or capacitors alone. Impedance combines reactance with resistance into a single value: Z = √(R² + X²). In a purely reactive circuit with no resistance, impedance equals the absolute value of the reactance.

Why does inductive reactance increase with frequency?

An inductor opposes changes in current. At higher frequencies the current changes direction more often, so the inductor resists more strongly. At DC (0 Hz), an ideal inductor has zero reactance and behaves like a short circuit.

How do you calculate capacitive reactance at 1 kHz?

Use Xᴄ = 1/(2πfC). For a 10 µF capacitor at 1,000 Hz: Xᴄ = 1/(2π × 1000 × 0.00001) ≈ 15.92 Ω. Larger capacitors or higher frequencies yield lower reactance.

What is power factor correction?

Industrial motors draw inductive current that lags behind the voltage, wasting energy. Adding capacitors reduces the net reactance, bringing current and voltage closer in phase. This lowers the apparent power demand and can reduce electricity costs by 10–30%.

Reference: Tipler, Paul A. 1995. Physics For Scientists and Engineers. Worth Publishers. 3rd ed.

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Reference: Tipler, Paul A. 1995. Physics For Scientists and Engineers. Worth Publishers. 3rd ed.